Base | Representation |
---|---|
bin | 110100100100101100100001… |
… | …111001001100101011110011 |
3 | 1010022200102120121212102210011 |
4 | 310210230201321030223303 |
5 | 220301302313023204301 |
6 | 2135433021313515351 |
7 | 66463050305413366 |
oct | 6444544171145363 |
9 | 1108612517772704 |
10 | 231220133022451 |
11 | 677459a9216221 |
12 | 21b24016872b57 |
13 | 9c02c710c6b61 |
14 | 411518532a0dd |
15 | 1bae8762e8a51 |
hex | d24b21e4caf3 |
231220133022451 has 2 divisors, whose sum is σ = 231220133022452. Its totient is φ = 231220133022450.
The previous prime is 231220133022419. The next prime is 231220133022503. The reversal of 231220133022451 is 154220331022132.
It is a happy number.
231220133022451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 231220133022451 - 25 = 231220133022419 is a prime.
It is not a weakly prime, because it can be changed into another prime (231220133022401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115610066511225 + 115610066511226.
It is an arithmetic number, because the mean of its divisors is an integer number (115610066511226).
Almost surely, 2231220133022451 is an apocalyptic number.
231220133022451 is a deficient number, since it is larger than the sum of its proper divisors (1).
231220133022451 is an equidigital number, since it uses as much as digits as its factorization.
231220133022451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 231220133022451 its reverse (154220331022132), we get a palindrome (385440464044583).
The spelling of 231220133022451 in words is "two hundred thirty-one trillion, two hundred twenty billion, one hundred thirty-three million, twenty-two thousand, four hundred fifty-one".
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