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2312241324433 is a prime number
BaseRepresentation
bin100001101001011100010…
…100101010000110010001
322012001022001222120221121
4201221130110222012101
5300340432234340213
64530121244122241
7326024331654055
oct41513424520621
98161261876847
102312241324433
11811685a47337
12314164b36381
1313a074520401
147dcad6abc65
15402301ca88d
hex21a5c52a191

2312241324433 has 2 divisors, whose sum is σ = 2312241324434. Its totient is φ = 2312241324432.

The previous prime is 2312241324329. The next prime is 2312241324439. The reversal of 2312241324433 is 3344231422132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1716802231824 + 595439092609 = 1310268^2 + 771647^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2312241324433 is a prime.

It is not a weakly prime, because it can be changed into another prime (2312241324439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1156120662216 + 1156120662217.

It is an arithmetic number, because the mean of its divisors is an integer number (1156120662217).

Almost surely, 22312241324433 is an apocalyptic number.

It is an amenable number.

2312241324433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2312241324433 is an equidigital number, since it uses as much as digits as its factorization.

2312241324433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 82944, while the sum is 34.

Adding to 2312241324433 its reverse (3344231422132), we get a palindrome (5656472746565).

The spelling of 2312241324433 in words is "two trillion, three hundred twelve billion, two hundred forty-one million, three hundred twenty-four thousand, four hundred thirty-three".