2312250433 has 2 divisors, whose sum is σ = 2312250434. Its totient is φ = 2312250432.

The previous prime is 2312250407. The next prime is 2312250487. The reversal of 2312250433 is 3340522132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1442708289 + 869542144 = 37983^2 + 29488^2 .

It is a cyclic number.

It is not a de Polignac number, because 2312250433 - 2¹⁷ = 2312119361 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2312250398 and 2312250407.

It is not a weakly prime, because it can be changed into another prime (2312250233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1156125216 + 1156125217.

It is an arithmetic number, because the mean of its divisors is an integer number (1156125217).

Almost surely, 2^2312250433 is an apocalyptic number.

It is an amenable number.

2312250433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2312250433 is an equidigital number, since it uses as much as digits as its factorization.

2312250433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 2312250433 is about 48085.8652100594. The cubic root of 2312250433 is about 1322.3455451925.

Adding to 2312250433 its reverse (3340522132), we get a palindrome (5652772565).

The spelling of 2312250433 in words is "two billion, three hundred twelve million, two hundred fifty thousand, four hundred thirty-three".