Base | Representation |
---|---|
bin | 100001101001100111110… |
… | …011110100110110001101 |
3 | 22012001210111121202220111 |
4 | 201221213303310312031 |
5 | 300341331103404201 |
6 | 4530152330520021 |
7 | 326032162030423 |
oct | 41514763646615 |
9 | 8161714552814 |
10 | 2312434044301 |
11 | 811774807657 |
12 | 3141b9596011 |
13 | 13a0a5428b34 |
14 | 7dccb117113 |
15 | 40242097b51 |
hex | 21a67cf4d8d |
2312434044301 has 2 divisors, whose sum is σ = 2312434044302. Its totient is φ = 2312434044300.
The previous prime is 2312434044293. The next prime is 2312434044313. The reversal of 2312434044301 is 1034404342132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2246698212201 + 65735832100 = 1498899^2 + 256390^2 .
It is a cyclic number.
It is not a de Polignac number, because 2312434044301 - 23 = 2312434044293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2312434044331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1156217022150 + 1156217022151.
It is an arithmetic number, because the mean of its divisors is an integer number (1156217022151).
Almost surely, 22312434044301 is an apocalyptic number.
It is an amenable number.
2312434044301 is a deficient number, since it is larger than the sum of its proper divisors (1).
2312434044301 is an equidigital number, since it uses as much as digits as its factorization.
2312434044301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 2312434044301 its reverse (1034404342132), we get a palindrome (3346838386433).
The spelling of 2312434044301 in words is "two trillion, three hundred twelve billion, four hundred thirty-four million, forty-four thousand, three hundred one".
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