23124914437 has 2 divisors, whose sum is σ = 23124914438. Its totient is φ = 23124914436.

The previous prime is 23124914387. The next prime is 23124914443. The reversal of 23124914437 is 73441942132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21106568961 + 2018345476 = 145281^2 + 44926^2 .

It is a cyclic number.

It is not a de Polignac number, because 23124914437 - 2¹¹ = 23124912389 is a prime.

It is a super-3 number, since 3×23124914437³ (a number of 32 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 23124914437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23124914467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11562457218 + 11562457219.

It is an arithmetic number, because the mean of its divisors is an integer number (11562457219).

Almost surely, 2^23124914437 is an apocalyptic number.

It is an amenable number.

23124914437 is a deficient number, since it is larger than the sum of its proper divisors (1).

23124914437 is an equidigital number, since it uses as much as digits as its factorization.

23124914437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 145152, while the sum is 40.

The spelling of 23124914437 in words is "twenty-three billion, one hundred twenty-four million, nine hundred fourteen thousand, four hundred thirty-seven".