23128384841 has 2 divisors, whose sum is σ = 23128384842. Its totient is φ = 23128384840.

The previous prime is 23128384823. The next prime is 23128384843. The reversal of 23128384841 is 14848382132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12923142400 + 10205242441 = 113680^2 + 101021^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-23128384841 is a prime.

Together with 23128384843, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 23128384792 and 23128384801.

It is not a weakly prime, because it can be changed into another prime (23128384843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11564192420 + 11564192421.

It is an arithmetic number, because the mean of its divisors is an integer number (11564192421).

Almost surely, 2^23128384841 is an apocalyptic number.

It is an amenable number.

23128384841 is a deficient number, since it is larger than the sum of its proper divisors (1).

23128384841 is an equidigital number, since it uses as much as digits as its factorization.

23128384841 is an evil number, because the sum of its binary digits is even.

The product of its digits is 294912, while the sum is 44.

The spelling of 23128384841 in words is "twenty-three billion, one hundred twenty-eight million, three hundred eighty-four thousand, eight hundred forty-one".