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2312952433193 is a prime number
BaseRepresentation
bin100001101010000110101…
…101010100101000101001
322012010010122001122210002
4201222012231110220221
5300343411310330233
64530320005432345
7326051055203333
oct41520655245051
98163118048702
102312952433193
11811a10393926
1231432310b6b5
1313a15894bc1c
147dd39cd8453
15402728446e8
hex21a86b54a29

2312952433193 has 2 divisors, whose sum is σ = 2312952433194. Its totient is φ = 2312952433192.

The previous prime is 2312952433123. The next prime is 2312952433217. The reversal of 2312952433193 is 3913342592132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1804822972969 + 508129460224 = 1343437^2 + 712832^2 .

It is a cyclic number.

It is not a de Polignac number, because 2312952433193 - 210 = 2312952432169 is a prime.

It is a super-3 number, since 3×23129524331933 (a number of 38 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (2312952433123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1156476216596 + 1156476216597.

It is an arithmetic number, because the mean of its divisors is an integer number (1156476216597).

Almost surely, 22312952433193 is an apocalyptic number.

It is an amenable number.

2312952433193 is a deficient number, since it is larger than the sum of its proper divisors (1).

2312952433193 is an equidigital number, since it uses as much as digits as its factorization.

2312952433193 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1049760, while the sum is 47.

The spelling of 2312952433193 in words is "two trillion, three hundred twelve billion, nine hundred fifty-two million, four hundred thirty-three thousand, one hundred ninety-three".