Base | Representation |
---|---|
bin | 100001101010001100001… |
… | …000011111111001100101 |
3 | 22012010100222022110011211 |
4 | 201222030020133321211 |
5 | 300344103110141201 |
6 | 4530333020231421 |
7 | 326053241604043 |
oct | 41521410377145 |
9 | 8163328273154 |
10 | 2313043443301 |
11 | 811a577a5098 |
12 | 31434969b571 |
13 | 13a171765866 |
14 | 7dd48029393 |
15 | 4027a820651 |
hex | 21a8c21fe65 |
2313043443301 has 16 divisors (see below), whose sum is σ = 2367207383040. Its totient is φ = 2259090691200.
The previous prime is 2313043443259. The next prime is 2313043443317. The reversal of 2313043443301 is 1033443403132.
It is a cyclic number.
It is not a de Polignac number, because 2313043443301 - 235 = 2278683704933 is a prime.
It is a super-4 number, since 4×23130434433014 (a number of 51 digits) contains 4444 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2313043443371) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 44820625 + ... + 44872201.
It is an arithmetic number, because the mean of its divisors is an integer number (147950461440).
Almost surely, 22313043443301 is an apocalyptic number.
It is an amenable number.
2313043443301 is a deficient number, since it is larger than the sum of its proper divisors (54163939739).
2313043443301 is a wasteful number, since it uses less digits than its factorization.
2313043443301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53604.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 2313043443301 its reverse (1033443403132), we get a palindrome (3346486846433).
The spelling of 2313043443301 in words is "two trillion, three hundred thirteen billion, forty-three million, four hundred forty-three thousand, three hundred one".
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