Base | Representation |
---|---|
bin | 100001101010010000001… |
… | …011000000110000010111 |
3 | 22012010112200211102000202 |
4 | 201222100023000300113 |
5 | 300344222432223111 |
6 | 4530343440531115 |
7 | 326055023612435 |
oct | 41522013006027 |
9 | 8163480742022 |
10 | 2313111211031 |
11 | 811a91a80a85 |
12 | 314368320a9b |
13 | 13a1828022ca |
14 | 7dd53029d55 |
15 | 40281759b3b |
hex | 21a902c0c17 |
2313111211031 has 2 divisors, whose sum is σ = 2313111211032. Its totient is φ = 2313111211030.
The previous prime is 2313111210989. The next prime is 2313111211063. The reversal of 2313111211031 is 1301121113132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2313111211031 - 218 = 2313110948887 is a prime.
It is a super-3 number, since 3×23131112110313 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 2313111210994 and 2313111211012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2313111231031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1156555605515 + 1156555605516.
It is an arithmetic number, because the mean of its divisors is an integer number (1156555605516).
Almost surely, 22313111211031 is an apocalyptic number.
2313111211031 is a deficient number, since it is larger than the sum of its proper divisors (1).
2313111211031 is an equidigital number, since it uses as much as digits as its factorization.
2313111211031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 2313111211031 its reverse (1301121113132), we get a palindrome (3614232324163).
The spelling of 2313111211031 in words is "two trillion, three hundred thirteen billion, one hundred eleven million, two hundred eleven thousand, thirty-one".
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