Base | Representation |
---|---|
bin | 1101011101101100110… |
… | …1111100001000010001 |
3 | 211010001110200221200121 |
4 | 3113123031330020101 |
5 | 12242211122144103 |
6 | 254132440150241 |
7 | 22466051113444 |
oct | 3273315741021 |
9 | 733043627617 |
10 | 231311131153 |
11 | 8a10a1154a3 |
12 | 389b5768381 |
13 | 18a7421890b |
14 | b2a470765b |
15 | 603c23b6bd |
hex | 35db37c211 |
231311131153 has 2 divisors, whose sum is σ = 231311131154. Its totient is φ = 231311131152.
The previous prime is 231311131087. The next prime is 231311131223. The reversal of 231311131153 is 351131113132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 167791002129 + 63520129024 = 409623^2 + 252032^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-231311131153 is a prime.
It is not a weakly prime, because it can be changed into another prime (231311161153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115655565576 + 115655565577.
It is an arithmetic number, because the mean of its divisors is an integer number (115655565577).
Almost surely, 2231311131153 is an apocalyptic number.
It is an amenable number.
231311131153 is a deficient number, since it is larger than the sum of its proper divisors (1).
231311131153 is an equidigital number, since it uses as much as digits as its factorization.
231311131153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 810, while the sum is 25.
Adding to 231311131153 its reverse (351131113132), we get a palindrome (582442244285).
The spelling of 231311131153 in words is "two hundred thirty-one billion, three hundred eleven million, one hundred thirty-one thousand, one hundred fifty-three".
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