Base | Representation |
---|---|
bin | 100001101010010000111… |
… | …100010011010111010011 |
3 | 22012010120121010212200112 |
4 | 201222100330103113103 |
5 | 300344234234213212 |
6 | 4530345021511535 |
7 | 326055241500002 |
oct | 41522074232723 |
9 | 8163517125615 |
10 | 2313124132307 |
11 | 811a992a6a1a |
12 | 3143707125ab |
13 | 13a1853a7731 |
14 | 7dd54a30c39 |
15 | 4028295d422 |
hex | 21a90f135d3 |
2313124132307 has 2 divisors, whose sum is σ = 2313124132308. Its totient is φ = 2313124132306.
The previous prime is 2313124132303. The next prime is 2313124132331. The reversal of 2313124132307 is 7032314213132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2313124132307 - 22 = 2313124132303 is a prime.
It is a super-2 number, since 2×23131241323072 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2313124132303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1156562066153 + 1156562066154.
It is an arithmetic number, because the mean of its divisors is an integer number (1156562066154).
Almost surely, 22313124132307 is an apocalyptic number.
2313124132307 is a deficient number, since it is larger than the sum of its proper divisors (1).
2313124132307 is an equidigital number, since it uses as much as digits as its factorization.
2313124132307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 32.
Adding to 2313124132307 its reverse (7032314213132), we get a palindrome (9345438345439).
The spelling of 2313124132307 in words is "two trillion, three hundred thirteen billion, one hundred twenty-four million, one hundred thirty-two thousand, three hundred seven".
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