Base | Representation |
---|---|
bin | 1010100001001101110110… |
… | …11100010100001111100111 |
3 | 10000220100120001022122020011 |
4 | 11100212323130110033213 |
5 | 11012441400133320203 |
6 | 121110252350351051 |
7 | 4605125133614323 |
oct | 520467334241747 |
9 | 100810501278204 |
10 | 23131543651303 |
11 | 740903a397a1a |
12 | 271706b1bb487 |
13 | cba3ab7521a9 |
14 | 59d803646983 |
15 | 2a1a87c0b76d |
hex | 1509bb7143e7 |
23131543651303 has 2 divisors, whose sum is σ = 23131543651304. Its totient is φ = 23131543651302.
The previous prime is 23131543651289. The next prime is 23131543651313. The reversal of 23131543651303 is 30315634513132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23131543651303 - 213 = 23131543643111 is a prime.
It is a super-2 number, since 2×231315436513032 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23131543651313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11565771825651 + 11565771825652.
It is an arithmetic number, because the mean of its divisors is an integer number (11565771825652).
Almost surely, 223131543651303 is an apocalyptic number.
23131543651303 is a deficient number, since it is larger than the sum of its proper divisors (1).
23131543651303 is an equidigital number, since it uses as much as digits as its factorization.
23131543651303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 291600, while the sum is 40.
The spelling of 23131543651303 in words is "twenty-three trillion, one hundred thirty-one billion, five hundred forty-three million, six hundred fifty-one thousand, three hundred three".
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