Base | Representation |
---|---|
bin | 100001101010010101101… |
… | …110100011001010110111 |
3 | 22012010210012012120020122 |
4 | 201222111232203022313 |
5 | 300344420312204421 |
6 | 4530401010322155 |
7 | 326060235042554 |
oct | 41522556431267 |
9 | 8163705176218 |
10 | 2313204413111 |
11 | 81202a64a099 |
12 | 31439358935b |
13 | 13a198c05877 |
14 | 7dd6156ba2b |
15 | 40289a1a2ab |
hex | 21a95ba32b7 |
2313204413111 has 2 divisors, whose sum is σ = 2313204413112. Its totient is φ = 2313204413110.
The previous prime is 2313204413089. The next prime is 2313204413189. The reversal of 2313204413111 is 1113144023132.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2313204413111 is a prime.
It is a super-4 number, since 4×23132044131114 (a number of 51 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2313204413011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1156602206555 + 1156602206556.
It is an arithmetic number, because the mean of its divisors is an integer number (1156602206556).
Almost surely, 22313204413111 is an apocalyptic number.
2313204413111 is a deficient number, since it is larger than the sum of its proper divisors (1).
2313204413111 is an equidigital number, since it uses as much as digits as its factorization.
2313204413111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 2313204413111 its reverse (1113144023132), we get a palindrome (3426348436243).
The spelling of 2313204413111 in words is "two trillion, three hundred thirteen billion, two hundred four million, four hundred thirteen thousand, one hundred eleven".
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