Base | Representation |
---|---|
bin | 1010100001001111100011… |
… | …00101011110001110000101 |
3 | 10000220102220100120121100220 |
4 | 11100213301211132032011 |
5 | 11013000230204134000 |
6 | 121110522440054553 |
7 | 4605156503622666 |
oct | 520476145361605 |
9 | 100812810517326 |
10 | 23132452021125 |
11 | 7409466116687 |
12 | 2717283464459 |
13 | cba4c49b9425 |
14 | 59d88c14136d |
15 | 2a1adc83d1a0 |
hex | 1509f195e385 |
23132452021125 has 64 divisors (see below), whose sum is σ = 38553204628224. Its totient is φ = 12317834880000.
The previous prime is 23132452021099. The next prime is 23132452021183. The reversal of 23132452021125 is 52112025423132.
It is not a de Polignac number, because 23132452021125 - 214 = 23132452004741 is a prime.
It is a super-2 number, since 2×231324520211252 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 629247745 + ... + 629284505.
It is an arithmetic number, because the mean of its divisors is an integer number (602393822316).
Almost surely, 223132452021125 is an apocalyptic number.
23132452021125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
23132452021125 is a deficient number, since it is larger than the sum of its proper divisors (15420752607099).
23132452021125 is a wasteful number, since it uses less digits than its factorization.
23132452021125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39383 (or 39373 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 23132452021125 its reverse (52112025423132), we get a palindrome (75244477444257).
The spelling of 23132452021125 in words is "twenty-three trillion, one hundred thirty-two billion, four hundred fifty-two million, twenty-one thousand, one hundred twenty-five".
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