Base | Representation |
---|---|
bin | 110100100110011101011011… |
… | …010010010111101110001011 |
3 | 1010100010000110210102021202101 |
4 | 310212131123102113232023 |
5 | 220310244043340204414 |
6 | 2140004430141414231 |
7 | 66504601303316506 |
oct | 6446353322275613 |
9 | 1110100423367671 |
10 | 231341355006859 |
11 | 67792354932309 |
12 | 21b4360786a377 |
13 | 9c1151c502106 |
14 | 411ada4a8613d |
15 | 1bb2abd6cda74 |
hex | d2675b497b8b |
231341355006859 has 2 divisors, whose sum is σ = 231341355006860. Its totient is φ = 231341355006858.
The previous prime is 231341355006857. The next prime is 231341355006871. The reversal of 231341355006859 is 958600553143132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 231341355006859 - 21 = 231341355006857 is a prime.
It is a super-3 number, since 3×2313413550068593 (a number of 44 digits) contains 333 as substring.
Together with 231341355006857, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (231341355006857) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115670677503429 + 115670677503430.
It is an arithmetic number, because the mean of its divisors is an integer number (115670677503430).
Almost surely, 2231341355006859 is an apocalyptic number.
231341355006859 is a deficient number, since it is larger than the sum of its proper divisors (1).
231341355006859 is an equidigital number, since it uses as much as digits as its factorization.
231341355006859 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11664000, while the sum is 55.
The spelling of 231341355006859 in words is "two hundred thirty-one trillion, three hundred forty-one billion, three hundred fifty-five million, six thousand, eight hundred fifty-nine".
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