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23134433201441 is a prime number
BaseRepresentation
bin1010100001010011001111…
…01011000100110100100001
310000220122000102111222211122
411100221213223010310201
511013013304344421231
6121111451211422025
74605256551442622
oct520514753046441
9100818012458748
1023134433201441
11740a292479791
122717736a54915
13cba74c2a4683
1459d9d92dba49
152a1ba673477b
hex150a67ac4d21

23134433201441 has 2 divisors, whose sum is σ = 23134433201442. Its totient is φ = 23134433201440.

The previous prime is 23134433201437. The next prime is 23134433201443. The reversal of 23134433201441 is 14410233443132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15026011795600 + 8108421405841 = 3876340^2 + 2847529^2 .

It is a cyclic number.

It is not a de Polignac number, because 23134433201441 - 22 = 23134433201437 is a prime.

Together with 23134433201443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (23134433201443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11567216600720 + 11567216600721.

It is an arithmetic number, because the mean of its divisors is an integer number (11567216600721).

Almost surely, 223134433201441 is an apocalyptic number.

It is an amenable number.

23134433201441 is a deficient number, since it is larger than the sum of its proper divisors (1).

23134433201441 is an equidigital number, since it uses as much as digits as its factorization.

23134433201441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 23134433201441 its reverse (14410233443132), we get a palindrome (37544666644573).

The spelling of 23134433201441 in words is "twenty-three trillion, one hundred thirty-four billion, four hundred thirty-three million, two hundred one thousand, four hundred forty-one".