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2313525414373 is a prime number
BaseRepresentation
bin100001101010101000110…
…111000100100111100101
322012011121120020010012021
4201222220313010213211
5300401100001224443
64530452514423141
7326101213361365
oct41525067044745
98164546203167
102313525414373
11812184868098
12314462b91ab1
1313a21a577744
147dd9204a9a5
15402a7cc69ed
hex21aa8dc49e5

2313525414373 has 2 divisors, whose sum is σ = 2313525414374. Its totient is φ = 2313525414372.

The previous prime is 2313525414311. The next prime is 2313525414391. The reversal of 2313525414373 is 3734145253132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2178673417089 + 134851997284 = 1476033^2 + 367222^2 .

It is a cyclic number.

It is not a de Polignac number, because 2313525414373 - 229 = 2312988543461 is a prime.

It is a super-2 number, since 2×23135254143732 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2313525417373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1156762707186 + 1156762707187.

It is an arithmetic number, because the mean of its divisors is an integer number (1156762707187).

Almost surely, 22313525414373 is an apocalyptic number.

It is an amenable number.

2313525414373 is a deficient number, since it is larger than the sum of its proper divisors (1).

2313525414373 is an equidigital number, since it uses as much as digits as its factorization.

2313525414373 is an evil number, because the sum of its binary digits is even.

The product of its digits is 907200, while the sum is 43.

The spelling of 2313525414373 in words is "two trillion, three hundred thirteen billion, five hundred twenty-five million, four hundred fourteen thousand, three hundred seventy-three".