Base | Representation |
---|---|
bin | 1010100001011111111011… |
… | …01101111110111001110101 |
3 | 10000221021121012002021221111 |
4 | 11100233331231332321311 |
5 | 11013121232322411313 |
6 | 121114535203115021 |
7 | 4605620431233343 |
oct | 520577555767165 |
9 | 100837535067844 |
10 | 23141245513333 |
11 | 741216888a512 |
12 | 2718b18372a71 |
13 | cbb29674425c |
14 | 5a0083d5c993 |
15 | 2a1e5482743d |
hex | 150bfdb7ee75 |
23141245513333 has 2 divisors, whose sum is σ = 23141245513334. Its totient is φ = 23141245513332.
The previous prime is 23141245513307. The next prime is 23141245513349. The reversal of 23141245513333 is 33331554214132.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20581891872529 + 2559353640804 = 4536727^2 + 1599798^2 .
It is a cyclic number.
It is not a de Polignac number, because 23141245513333 - 217 = 23141245382261 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23141245513303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11570622756666 + 11570622756667.
It is an arithmetic number, because the mean of its divisors is an integer number (11570622756667).
Almost surely, 223141245513333 is an apocalyptic number.
It is an amenable number.
23141245513333 is a deficient number, since it is larger than the sum of its proper divisors (1).
23141245513333 is an equidigital number, since it uses as much as digits as its factorization.
23141245513333 is an evil number, because the sum of its binary digits is even.
The product of its digits is 388800, while the sum is 40.
Adding to 23141245513333 its reverse (33331554214132), we get a palindrome (56472799727465).
The spelling of 23141245513333 in words is "twenty-three trillion, one hundred forty-one billion, two hundred forty-five million, five hundred thirteen thousand, three hundred thirty-three".
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