Base | Representation |
---|---|
bin | 100001101011001101100… |
… | …000100000010100001111 |
3 | 22012020012102011021122222 |
4 | 201223031200200110033 |
5 | 300403324401134003 |
6 | 4531033520525555 |
7 | 326122360422206 |
oct | 41531540402417 |
9 | 8166172137588 |
10 | 2314140255503 |
11 | 81246a93235a |
12 | 3145b4a808bb |
13 | 13a2b7a6b56b |
14 | 8000d97823d |
15 | 402e1c76c38 |
hex | 21acd82050f |
2314140255503 has 2 divisors, whose sum is σ = 2314140255504. Its totient is φ = 2314140255502.
The previous prime is 2314140255421. The next prime is 2314140255569. The reversal of 2314140255503 is 3055520414132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2314140255503 - 224 = 2314123478287 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2314140255803) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1157070127751 + 1157070127752.
It is an arithmetic number, because the mean of its divisors is an integer number (1157070127752).
Almost surely, 22314140255503 is an apocalyptic number.
2314140255503 is a deficient number, since it is larger than the sum of its proper divisors (1).
2314140255503 is an equidigital number, since it uses as much as digits as its factorization.
2314140255503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 2314140255503 its reverse (3055520414132), we get a palindrome (5369660669635).
The spelling of 2314140255503 in words is "two trillion, three hundred fourteen billion, one hundred forty million, two hundred fifty-five thousand, five hundred three".
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