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2314313404111 is a prime number
BaseRepresentation
bin100001101011010111110…
…101000000111011001111
322012020122110222010220101
4201223113311000323033
5300404203212412421
64531103024031531
7326126562233512
oct41532765007317
98166573863811
102314313404111
11812549645485
12314642a625a7
1313a3148b3a67
148002896ad79
154030207a191
hex21ad7d40ecf

2314313404111 has 2 divisors, whose sum is σ = 2314313404112. Its totient is φ = 2314313404110.

The previous prime is 2314313404057. The next prime is 2314313404127. The reversal of 2314313404111 is 1114043134132.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2314313404111 is a prime.

It is a super-4 number, since 4×23143134041114 (a number of 51 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2314313404111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2314313404211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1157156702055 + 1157156702056.

It is an arithmetic number, because the mean of its divisors is an integer number (1157156702056).

Almost surely, 22314313404111 is an apocalyptic number.

2314313404111 is a deficient number, since it is larger than the sum of its proper divisors (1).

2314313404111 is an equidigital number, since it uses as much as digits as its factorization.

2314313404111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 2314313404111 its reverse (1114043134132), we get a palindrome (3428356538243).

The spelling of 2314313404111 in words is "two trillion, three hundred fourteen billion, three hundred thirteen million, four hundred four thousand, one hundred eleven".