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23144131151 is a prime number
BaseRepresentation
bin10101100011011111…
…110110101001001111
32012201221202200100122
4111203133312221033
5334344344144101
614344323015155
71446350604011
oct254337665117
965657680318
1023144131151
1198a7293319
12459ab0a4bb
13224abb497b
141197aca1b1
15906cd051b
hex5637f6a4f

23144131151 has 2 divisors, whose sum is σ = 23144131152. Its totient is φ = 23144131150.

The previous prime is 23144131039. The next prime is 23144131169. The reversal of 23144131151 is 15113144132.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23144131151 is a prime.

It is a super-3 number, since 3×231441311513 (a number of 32 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 23144131151.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23144134151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11572065575 + 11572065576.

It is an arithmetic number, because the mean of its divisors is an integer number (11572065576).

Almost surely, 223144131151 is an apocalyptic number.

23144131151 is a deficient number, since it is larger than the sum of its proper divisors (1).

23144131151 is an equidigital number, since it uses as much as digits as its factorization.

23144131151 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1440, while the sum is 26.

Adding to 23144131151 its reverse (15113144132), we get a palindrome (38257275283).

The spelling of 23144131151 in words is "twenty-three billion, one hundred forty-four million, one hundred thirty-one thousand, one hundred fifty-one".