Base | Representation |
---|---|
bin | 110100100111111101001111… |
… | …110001011010111100100111 |
3 | 1010100110212001002122001101222 |
4 | 310213331033301122330213 |
5 | 220313440301201110142 |
6 | 2140124003322210555 |
7 | 66515203023164405 |
oct | 6447751761327447 |
9 | 1110425032561358 |
10 | 231444241035047 |
11 | 67821a51364077 |
12 | 21b5b540053a5b |
13 | 9c1b137bccc31 |
14 | 4121d65122475 |
15 | 1bb55e0e97bd2 |
hex | d27f4fc5af27 |
231444241035047 has 2 divisors, whose sum is σ = 231444241035048. Its totient is φ = 231444241035046.
The previous prime is 231444241034989. The next prime is 231444241035151. The reversal of 231444241035047 is 740530142444132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 231444241035047 - 28 = 231444241034791 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 231444241034989 and 231444241035007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (231444241032047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115722120517523 + 115722120517524.
It is an arithmetic number, because the mean of its divisors is an integer number (115722120517524).
Almost surely, 2231444241035047 is an apocalyptic number.
231444241035047 is a deficient number, since it is larger than the sum of its proper divisors (1).
231444241035047 is an equidigital number, since it uses as much as digits as its factorization.
231444241035047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1290240, while the sum is 44.
Adding to 231444241035047 its reverse (740530142444132), we get a palindrome (971974383479179).
The spelling of 231444241035047 in words is "two hundred thirty-one trillion, four hundred forty-four billion, two hundred forty-one million, thirty-five thousand, forty-seven".
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