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231444312401 is a prime number
BaseRepresentation
bin1101011110001100100…
…1111111000101010001
3211010101202022021000102
43113203021333011101
512242444220444101
6254153554502145
722502256124121
oct3274311770521
9733352267012
10231444312401
118a17830a545
1238a32294955
1318a959a93a3
14b2b8294c81
156048c9786b
hex35e327f151

231444312401 has 2 divisors, whose sum is σ = 231444312402. Its totient is φ = 231444312400.

The previous prime is 231444312373. The next prime is 231444312403. The reversal of 231444312401 is 104213444132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 225762771025 + 5681541376 = 475145^2 + 75376^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-231444312401 is a prime.

Together with 231444312403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (231444312403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115722156200 + 115722156201.

It is an arithmetic number, because the mean of its divisors is an integer number (115722156201).

Almost surely, 2231444312401 is an apocalyptic number.

It is an amenable number.

231444312401 is a deficient number, since it is larger than the sum of its proper divisors (1).

231444312401 is an equidigital number, since it uses as much as digits as its factorization.

231444312401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 231444312401 its reverse (104213444132), we get a palindrome (335657756533).

The spelling of 231444312401 in words is "two hundred thirty-one billion, four hundred forty-four million, three hundred twelve thousand, four hundred one".