Base | Representation |
---|---|
bin | 1010100001100111011000… |
… | …00011000010101110001011 |
3 | 10000221122220211222001010121 |
4 | 11100303230003002232023 |
5 | 11013202424431331103 |
6 | 121120440040524111 |
7 | 4606121503013203 |
oct | 520635403025613 |
9 | 100848824861117 |
10 | 23145244011403 |
11 | 741392a938278 |
12 | 2719853480637 |
13 | cbb782c5b147 |
14 | 5a0343001403 |
15 | 2a20da8a26bd |
hex | 150cec0c2b8b |
23145244011403 has 2 divisors, whose sum is σ = 23145244011404. Its totient is φ = 23145244011402.
The previous prime is 23145244011377. The next prime is 23145244011443. The reversal of 23145244011403 is 30411044254132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23145244011403 - 237 = 23007805057931 is a prime.
It is not a weakly prime, because it can be changed into another prime (23145244011443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11572622005701 + 11572622005702.
It is an arithmetic number, because the mean of its divisors is an integer number (11572622005702).
Almost surely, 223145244011403 is an apocalyptic number.
23145244011403 is a deficient number, since it is larger than the sum of its proper divisors (1).
23145244011403 is an equidigital number, since it uses as much as digits as its factorization.
23145244011403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46080, while the sum is 34.
Adding to 23145244011403 its reverse (30411044254132), we get a palindrome (53556288265535).
The spelling of 23145244011403 in words is "twenty-three trillion, one hundred forty-five billion, two hundred forty-four million, eleven thousand, four hundred three".
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