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23145433 is a prime number
BaseRepresentation
bin101100001001…
…0101111011001
31121112220120021
41120102233121
521411123213
62144030441
7400506253
oct130225731
947486507
1023145433
1112079563
127902421
134a4502c
143106cd3
152072d8d
hex1612bd9

23145433 has 2 divisors, whose sum is σ = 23145434. Its totient is φ = 23145432.

The previous prime is 23145407. The next prime is 23145457. The reversal of 23145433 is 33454132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20142144 + 3003289 = 4488^2 + 1733^2 .

It is a cyclic number.

It is not a de Polignac number, because 23145433 - 29 = 23144921 is a prime.

It is a super-2 number, since 2×231454332 = 1071422137514978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23145398 and 23145407.

It is not a weakly prime, because it can be changed into another prime (23145533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11572716 + 11572717.

It is an arithmetic number, because the mean of its divisors is an integer number (11572717).

Almost surely, 223145433 is an apocalyptic number.

It is an amenable number.

23145433 is a deficient number, since it is larger than the sum of its proper divisors (1).

23145433 is an equidigital number, since it uses as much as digits as its factorization.

23145433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4320, while the sum is 25.

The square root of 23145433 is about 4810.9700684997. The cubic root of 23145433 is about 284.9848478658.

Adding to 23145433 its reverse (33454132), we get a palindrome (56599565).

The spelling of 23145433 in words is "twenty-three million, one hundred forty-five thousand, four hundred thirty-three".