Base | Representation |
---|---|
bin | 1010100001110110010010… |
… | …10100100100111101100110 |
3 | 10000222102120220011111011101 |
4 | 11100323021110210331212 |
5 | 11013320324320341014 |
6 | 121124242401430314 |
7 | 4606524103126006 |
oct | 520731124447546 |
9 | 100872526144141 |
10 | 23153251340134 |
11 | 7417269860923 |
12 | 271b30903b39a |
13 | cbc45ab68c96 |
14 | 5a08a2656006 |
15 | 2a2408849474 |
hex | 150ec9524f66 |
23153251340134 has 8 divisors (see below), whose sum is σ = 35927458976160. Its totient is φ = 11177431681416.
The previous prime is 23153251340123. The next prime is 23153251340251. The reversal of 23153251340134 is 43104315235132.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 23153251340093 and 23153251340102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 199596994254 + ... + 199596994369.
It is an arithmetic number, because the mean of its divisors is an integer number (4490932372020).
Almost surely, 223153251340134 is an apocalyptic number.
23153251340134 is a deficient number, since it is larger than the sum of its proper divisors (12774207636026).
23153251340134 is a wasteful number, since it uses less digits than its factorization.
23153251340134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 399193988654.
The product of its (nonzero) digits is 129600, while the sum is 37.
Adding to 23153251340134 its reverse (43104315235132), we get a palindrome (66257566575266).
The spelling of 23153251340134 in words is "twenty-three trillion, one hundred fifty-three billion, two hundred fifty-one million, three hundred forty thousand, one hundred thirty-four".
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