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23153251340134 = 229399193988623
BaseRepresentation
bin1010100001110110010010…
…10100100100111101100110
310000222102120220011111011101
411100323021110210331212
511013320324320341014
6121124242401430314
74606524103126006
oct520731124447546
9100872526144141
1023153251340134
117417269860923
12271b30903b39a
13cbc45ab68c96
145a08a2656006
152a2408849474
hex150ec9524f66

23153251340134 has 8 divisors (see below), whose sum is σ = 35927458976160. Its totient is φ = 11177431681416.

The previous prime is 23153251340123. The next prime is 23153251340251. The reversal of 23153251340134 is 43104315235132.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 23153251340093 and 23153251340102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 199596994254 + ... + 199596994369.

It is an arithmetic number, because the mean of its divisors is an integer number (4490932372020).

Almost surely, 223153251340134 is an apocalyptic number.

23153251340134 is a deficient number, since it is larger than the sum of its proper divisors (12774207636026).

23153251340134 is a wasteful number, since it uses less digits than its factorization.

23153251340134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 399193988654.

The product of its (nonzero) digits is 129600, while the sum is 37.

Adding to 23153251340134 its reverse (43104315235132), we get a palindrome (66257566575266).

The spelling of 23153251340134 in words is "twenty-three trillion, one hundred fifty-three billion, two hundred fifty-one million, three hundred forty thousand, one hundred thirty-four".

Divisors: 1 2 29 58 399193988623 798387977246 11576625670067 23153251340134