Base | Representation |
---|---|
bin | 100001101100010110010… |
… | …010100011001100100011 |
3 | 22012100100111211111112101 |
4 | 201230112102203030203 |
5 | 300413330000142201 |
6 | 4531355020511231 |
7 | 326164545421033 |
oct | 41542622431443 |
9 | 8170314744471 |
10 | 2315361334051 |
11 | 812a37125787 |
12 | 3148959ab517 |
13 | 13a450a3304c |
14 | 800c7bd38c3 |
15 | 40364077d01 |
hex | 21b164a3323 |
2315361334051 has 2 divisors, whose sum is σ = 2315361334052. Its totient is φ = 2315361334050.
The previous prime is 2315361334037. The next prime is 2315361334057. The reversal of 2315361334051 is 1504331635132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2315361334051 - 215 = 2315361301283 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2315361334051.
It is not a weakly prime, because it can be changed into another prime (2315361334057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1157680667025 + 1157680667026.
It is an arithmetic number, because the mean of its divisors is an integer number (1157680667026).
Almost surely, 22315361334051 is an apocalyptic number.
2315361334051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2315361334051 is an equidigital number, since it uses as much as digits as its factorization.
2315361334051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 37.
Adding to 2315361334051 its reverse (1504331635132), we get a palindrome (3819692969183).
The spelling of 2315361334051 in words is "two trillion, three hundred fifteen billion, three hundred sixty-one million, three hundred thirty-four thousand, fifty-one".
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