Base | Representation |
---|---|
bin | 100001101100010110010… |
… | …010100011001100101001 |
3 | 22012100100111211111112121 |
4 | 201230112102203030221 |
5 | 300413330000142212 |
6 | 4531355020511241 |
7 | 326164545421042 |
oct | 41542622431451 |
9 | 8170314744477 |
10 | 2315361334057 |
11 | 812a37125792 |
12 | 3148959ab521 |
13 | 13a450a33055 |
14 | 800c7bd38c9 |
15 | 40364077d07 |
hex | 21b164a3329 |
2315361334057 has 2 divisors, whose sum is σ = 2315361334058. Its totient is φ = 2315361334056.
The previous prime is 2315361334051. The next prime is 2315361334063. The reversal of 2315361334057 is 7504331635132.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (2315361334051) and next prime (2315361334063).
It can be written as a sum of positive squares in only one way, i.e., 2101192303401 + 214169030656 = 1449549^2 + 462784^2 .
It is a cyclic number.
It is not a de Polignac number, because 2315361334057 - 235 = 2281001595689 is a prime.
It is not a weakly prime, because it can be changed into another prime (2315361334051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1157680667028 + 1157680667029.
It is an arithmetic number, because the mean of its divisors is an integer number (1157680667029).
Almost surely, 22315361334057 is an apocalyptic number.
It is an amenable number.
2315361334057 is a deficient number, since it is larger than the sum of its proper divisors (1).
2315361334057 is an equidigital number, since it uses as much as digits as its factorization.
2315361334057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 680400, while the sum is 43.
Adding to 2315361334057 its reverse (7504331635132), we get a palindrome (9819692969189).
The spelling of 2315361334057 in words is "two trillion, three hundred fifteen billion, three hundred sixty-one million, three hundred thirty-four thousand, fifty-seven".
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