Base | Representation |
---|---|
bin | 10101100100000101… |
… | …100100111110011011 |
3 | 2012202122101002122121 |
4 | 111210011210332123 |
5 | 334404412122001 |
6 | 14345315002111 |
7 | 1446530632135 |
oct | 254405447633 |
9 | 65678332577 |
10 | 23154020251 |
11 | 990192812a |
12 | 45a2299337 |
13 | 224cc67bcb |
14 | 1199142055 |
15 | 907ad56a1 |
hex | 564164f9b |
23154020251 has 2 divisors, whose sum is σ = 23154020252. Its totient is φ = 23154020250.
The previous prime is 23154020237. The next prime is 23154020257. The reversal of 23154020251 is 15202045132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23154020251 - 29 = 23154019739 is a prime.
It is a super-3 number, since 3×231540202513 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (23154020257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11577010125 + 11577010126.
It is an arithmetic number, because the mean of its divisors is an integer number (11577010126).
Almost surely, 223154020251 is an apocalyptic number.
23154020251 is a deficient number, since it is larger than the sum of its proper divisors (1).
23154020251 is an equidigital number, since it uses as much as digits as its factorization.
23154020251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 23154020251 its reverse (15202045132), we get a palindrome (38356065383).
The spelling of 23154020251 in words is "twenty-three billion, one hundred fifty-four million, twenty thousand, two hundred fifty-one".
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