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231553492683701 is a prime number
BaseRepresentation
bin110100101001100010111111…
…101011011000101110110101
31010100212022001000212211201112
4310221202333223120232311
5220322233023111334301
62140250112300204405
766526121256653456
oct6451427753305665
91110768030784645
10231553492683701
116786431503a7a1
1221b78750239705
139c2852935b896
14412736ab8312d
151bb838751b9bb
hexd298bfad8bb5

231553492683701 has 2 divisors, whose sum is σ = 231553492683702. Its totient is φ = 231553492683700.

The previous prime is 231553492683619. The next prime is 231553492683787. The reversal of 231553492683701 is 107386294355132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121651502621476 + 109901990062225 = 11029574^2 + 10483415^2 .

It is a cyclic number.

It is not a de Polignac number, because 231553492683701 - 238 = 231278614776757 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (231553492683001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115776746341850 + 115776746341851.

It is an arithmetic number, because the mean of its divisors is an integer number (115776746341851).

It is a 2-persistent number, because it is pandigital, and so is 2⋅231553492683701 = 463106985367402, but 3⋅231553492683701 = 694660478051103 is not.

Almost surely, 2231553492683701 is an apocalyptic number.

It is an amenable number.

231553492683701 is a deficient number, since it is larger than the sum of its proper divisors (1).

231553492683701 is an equidigital number, since it uses as much as digits as its factorization.

231553492683701 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32659200, while the sum is 59.

The spelling of 231553492683701 in words is "two hundred thirty-one trillion, five hundred fifty-three billion, four hundred ninety-two million, six hundred eighty-three thousand, seven hundred one".