Base | Representation |
---|---|
bin | 100001101100100001001… |
… | …001001100001111101001 |
3 | 22012100211012110221101021 |
4 | 201230201021030033221 |
5 | 300414213104230441 |
6 | 4531425043452441 |
7 | 326202216256255 |
oct | 41544111141751 |
9 | 8170735427337 |
10 | 2315543430121 |
11 | 81301a99a1a9 |
12 | 314926987121 |
13 | 13a47c68bcbc |
14 | 80104075265 |
15 | 403750473d1 |
hex | 21b2124c3e9 |
2315543430121 has 2 divisors, whose sum is σ = 2315543430122. Its totient is φ = 2315543430120.
The previous prime is 2315543430089. The next prime is 2315543430181. The reversal of 2315543430121 is 1210343455132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2231811905625 + 83731524496 = 1493925^2 + 289364^2 .
It is a cyclic number.
It is not a de Polignac number, because 2315543430121 - 25 = 2315543430089 is a prime.
It is not a weakly prime, because it can be changed into another prime (2315543430181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1157771715060 + 1157771715061.
It is an arithmetic number, because the mean of its divisors is an integer number (1157771715061).
Almost surely, 22315543430121 is an apocalyptic number.
It is an amenable number.
2315543430121 is a deficient number, since it is larger than the sum of its proper divisors (1).
2315543430121 is an equidigital number, since it uses as much as digits as its factorization.
2315543430121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 2315543430121 its reverse (1210343455132), we get a palindrome (3525886885253).
The spelling of 2315543430121 in words is "two trillion, three hundred fifteen billion, five hundred forty-three million, four hundred thirty thousand, one hundred twenty-one".
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