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23156852832017 is a prime number
BaseRepresentation
bin1010100001111100111111…
…11111001011011100010001
310000222202212220000020020122
411100332133333023130101
511013400213311111032
6121130040014120025
74610012254243232
oct520763777133421
9100882786006218
1023156852832017
1174188477a8aa3
12271bb531b0015
13cbc8b304c178
145a0b24ab3089
152a2569b03012
hex150f9ffcb711

23156852832017 has 2 divisors, whose sum is σ = 23156852832018. Its totient is φ = 23156852832016.

The previous prime is 23156852831977. The next prime is 23156852832037. The reversal of 23156852832017 is 71023825865132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19903161999616 + 3253690832401 = 4461296^2 + 1803799^2 .

It is a cyclic number.

It is not a de Polignac number, because 23156852832017 - 236 = 23088133355281 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 23156852832017.

It is not a weakly prime, because it can be changed into another prime (23156852832037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11578426416008 + 11578426416009.

It is an arithmetic number, because the mean of its divisors is an integer number (11578426416009).

Almost surely, 223156852832017 is an apocalyptic number.

It is an amenable number.

23156852832017 is a deficient number, since it is larger than the sum of its proper divisors (1).

23156852832017 is an equidigital number, since it uses as much as digits as its factorization.

23156852832017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4838400, while the sum is 53.

The spelling of 23156852832017 in words is "twenty-three trillion, one hundred fifty-six billion, eight hundred fifty-two million, eight hundred thirty-two thousand, seventeen".