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23162140117 is a prime number
BaseRepresentation
bin10101100100100100…
…100011010111010101
32012210012122122000101
4111210210203113111
5334414001440432
614350205014101
71446656641204
oct254444432725
965705578011
1023162140117
119906473766
1245a4b54331
13225184ba6c
14119a25723b
1590868b4e7
hex5649235d5

23162140117 has 2 divisors, whose sum is σ = 23162140118. Its totient is φ = 23162140116.

The previous prime is 23162140109. The next prime is 23162140129. The reversal of 23162140117 is 71104126132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15517435761 + 7644704356 = 124569^2 + 87434^2 .

It is a cyclic number.

It is not a de Polignac number, because 23162140117 - 23 = 23162140109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23162140147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11581070058 + 11581070059.

It is an arithmetic number, because the mean of its divisors is an integer number (11581070059).

Almost surely, 223162140117 is an apocalyptic number.

It is an amenable number.

23162140117 is a deficient number, since it is larger than the sum of its proper divisors (1).

23162140117 is an equidigital number, since it uses as much as digits as its factorization.

23162140117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 28.

Adding to 23162140117 its reverse (71104126132), we get a palindrome (94266266249).

The spelling of 23162140117 in words is "twenty-three billion, one hundred sixty-two million, one hundred forty thousand, one hundred seventeen".