Base | Representation |
---|---|
bin | 100001101101010110001… |
… | …011000101110011000011 |
3 | 22012110010012120220001222 |
4 | 201231112023011303003 |
5 | 300423023334323301 |
6 | 4532053224545255 |
7 | 326233241435522 |
oct | 41552613056303 |
9 | 8173105526058 |
10 | 2316433120451 |
11 | 81343711a76a |
12 | 314b3492222b |
13 | 13a591ab5b98 |
14 | 8018a2aa4b9 |
15 | 403c81d931b |
hex | 21b562c5cc3 |
2316433120451 has 2 divisors, whose sum is σ = 2316433120452. Its totient is φ = 2316433120450.
The previous prime is 2316433120433. The next prime is 2316433120453. The reversal of 2316433120451 is 1540213346132.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2316433120451 is a prime.
Together with 2316433120453, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2316433120453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1158216560225 + 1158216560226.
It is an arithmetic number, because the mean of its divisors is an integer number (1158216560226).
Almost surely, 22316433120451 is an apocalyptic number.
2316433120451 is a deficient number, since it is larger than the sum of its proper divisors (1).
2316433120451 is an equidigital number, since it uses as much as digits as its factorization.
2316433120451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 35.
Adding to 2316433120451 its reverse (1540213346132), we get a palindrome (3856646466583).
The spelling of 2316433120451 in words is "two trillion, three hundred sixteen billion, four hundred thirty-three million, one hundred twenty thousand, four hundred fifty-one".
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