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232013121113 is a prime number
BaseRepresentation
bin1101100000010100001…
…1110100011001011001
3211011212101121201212202
43120011003310121121
512300130324333423
6254330234215545
722522333663424
oct3300503643131
9734771551782
10232013121113
118a43a3a3994
1238b708845b5
1318b567a39a7
14b32da3c9bb
15607dba3728
hex36050f4659

232013121113 has 2 divisors, whose sum is σ = 232013121114. Its totient is φ = 232013121112.

The previous prime is 232013121107. The next prime is 232013121143. The reversal of 232013121113 is 311121310232.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 175165686784 + 56847434329 = 418528^2 + 238427^2 .

It is a cyclic number.

It is not a de Polignac number, because 232013121113 - 230 = 230939379289 is a prime.

It is not a weakly prime, because it can be changed into another prime (232013121143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116006560556 + 116006560557.

It is an arithmetic number, because the mean of its divisors is an integer number (116006560557).

Almost surely, 2232013121113 is an apocalyptic number.

It is an amenable number.

232013121113 is a deficient number, since it is larger than the sum of its proper divisors (1).

232013121113 is an equidigital number, since it uses as much as digits as its factorization.

232013121113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 232013121113 its reverse (311121310232), we get a palindrome (543134431345).

The spelling of 232013121113 in words is "two hundred thirty-two billion, thirteen million, one hundred twenty-one thousand, one hundred thirteen".