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232013395933433 is a prime number
BaseRepresentation
bin110100110000001111010100…
…000011000011100011111001
31010102111021010110222121001022
4310300033110003003203321
5220402301413324332213
62141241252131032225
766604262145043442
oct6460172403034371
91112437113877038
10232013395933433
1167a21368478254
1222031900a3b675
139c5ca0038080a
144141718a122c9
151bc5302e06308
hexd303d40c38f9

232013395933433 has 2 divisors, whose sum is σ = 232013395933434. Its totient is φ = 232013395933432.

The previous prime is 232013395933411. The next prime is 232013395933493. The reversal of 232013395933433 is 334339593310232.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 226426564065529 + 5586831867904 = 15047477^2 + 2363648^2 .

It is a cyclic number.

It is not a de Polignac number, because 232013395933433 - 220 = 232013394884857 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (232013395933493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116006697966716 + 116006697966717.

It is an arithmetic number, because the mean of its divisors is an integer number (116006697966717).

Almost surely, 2232013395933433 is an apocalyptic number.

It is an amenable number.

232013395933433 is a deficient number, since it is larger than the sum of its proper divisors (1).

232013395933433 is an equidigital number, since it uses as much as digits as its factorization.

232013395933433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14171760, while the sum is 53.

The spelling of 232013395933433 in words is "two hundred thirty-two trillion, thirteen billion, three hundred ninety-five million, nine hundred thirty-three thousand, four hundred thirty-three".