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23202543130142 = 211601271565071
BaseRepresentation
bin1010100011010010000110…
…10101110101011000011110
310001011010211010100212022112
411101221003111311120132
511020122302020131032
6121203033503514022
74613220435334415
oct521510325653036
9101133733325275
1023202543130142
117436163787262
1227289848b8912
13cc3cb4c8372c
145a301acb247c
152a3840e491b2
hex151a4357561e

23202543130142 has 4 divisors (see below), whose sum is σ = 34803814695216. Its totient is φ = 11601271565070.

The previous prime is 23202543130061. The next prime is 23202543130157. The reversal of 23202543130142 is 24103134520232.

It is a semiprime because it is the product of two primes.

It is a super-4 number, since 4×232025431301424 (a number of 55 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23202543130099 and 23202543130108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5800635782534 + ... + 5800635782537.

It is an arithmetic number, because the mean of its divisors is an integer number (8700953673804).

Almost surely, 223202543130142 is an apocalyptic number.

23202543130142 is a deficient number, since it is larger than the sum of its proper divisors (11601271565074).

23202543130142 is a wasteful number, since it uses less digits than its factorization.

23202543130142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11601271565073.

The product of its (nonzero) digits is 34560, while the sum is 32.

Adding to 23202543130142 its reverse (24103134520232), we get a palindrome (47305677650374).

The spelling of 23202543130142 in words is "twenty-three trillion, two hundred two billion, five hundred forty-three million, one hundred thirty thousand, one hundred forty-two".

Divisors: 1 2 11601271565071 23202543130142