Base | Representation |
---|---|
bin | 100001110001000101000… |
… | …000100101101100010011 |
3 | 22012211110110110200000121 |
4 | 201301011000211230103 |
5 | 301004230132402011 |
6 | 4533555004531111 |
7 | 326434445413255 |
oct | 41610500455423 |
9 | 8184413420017 |
10 | 2320440122131 |
11 | 815102a563aa |
12 | 315872850a97 |
13 | 13aa7ccb94b1 |
14 | 8044a523cd5 |
15 | 4055ed93e71 |
hex | 21c45025b13 |
2320440122131 has 2 divisors, whose sum is σ = 2320440122132. Its totient is φ = 2320440122130.
The previous prime is 2320440122089. The next prime is 2320440122167. The reversal of 2320440122131 is 1312210440232.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2320440122131 - 241 = 121416866579 is a prime.
It is a super-2 number, since 2×23204401221312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2320440122096 and 2320440122105.
It is not a weakly prime, because it can be changed into another prime (2320440122171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1160220061065 + 1160220061066.
It is an arithmetic number, because the mean of its divisors is an integer number (1160220061066).
Almost surely, 22320440122131 is an apocalyptic number.
2320440122131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2320440122131 is an equidigital number, since it uses as much as digits as its factorization.
2320440122131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2320440122131 its reverse (1312210440232), we get a palindrome (3632650562363).
The spelling of 2320440122131 in words is "two trillion, three hundred twenty billion, four hundred forty million, one hundred twenty-two thousand, one hundred thirty-one".
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