Base | Representation |
---|---|
bin | 110100110001100011000011… |
… | …011010010001111000011111 |
3 | 1010102210212012211021102200122 |
4 | 310301203003122101320133 |
5 | 220410240040121400301 |
6 | 2141350442241345155 |
7 | 66613624264404263 |
oct | 6461430332217037 |
9 | 1112725184242618 |
10 | 232103311121951 |
11 | 67a56509231205 |
12 | 220472153381bb |
13 | 9c6832c749689 |
14 | 4145c085540a3 |
15 | 1bc7816acd81b |
hex | d318c3691e1f |
232103311121951 has 2 divisors, whose sum is σ = 232103311121952. Its totient is φ = 232103311121950.
The previous prime is 232103311121947. The next prime is 232103311122041. The reversal of 232103311121951 is 159121113301232.
232103311121951 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 232103311121951 - 22 = 232103311121947 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (232100311121951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116051655560975 + 116051655560976.
It is an arithmetic number, because the mean of its divisors is an integer number (116051655560976).
Almost surely, 2232103311121951 is an apocalyptic number.
232103311121951 is a deficient number, since it is larger than the sum of its proper divisors (1).
232103311121951 is an equidigital number, since it uses as much as digits as its factorization.
232103311121951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 35.
The spelling of 232103311121951 in words is "two hundred thirty-two trillion, one hundred three billion, three hundred eleven million, one hundred twenty-one thousand, nine hundred fifty-one".
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