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232112003331347 is a prime number
BaseRepresentation
bin110100110001101011001001…
…100000011011010100010011
31010102211200122121012102100222
4310301223021200123110103
5220410410340323100342
62141354440545503255
766614352552100526
oct6461531140332423
91112750577172328
10232112003331347
1167a5a169807837
1222048a40341b2b
139c690b6501b49
1441463d0b28bbd
151bc7b74c5ced2
hexd31ac981b513

232112003331347 has 2 divisors, whose sum is σ = 232112003331348. Its totient is φ = 232112003331346.

The previous prime is 232112003331283. The next prime is 232112003331349. The reversal of 232112003331347 is 743133300211232.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 232112003331347 - 26 = 232112003331283 is a prime.

Together with 232112003331349, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (232112003331349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116056001665673 + 116056001665674.

It is an arithmetic number, because the mean of its divisors is an integer number (116056001665674).

Almost surely, 2232112003331347 is an apocalyptic number.

232112003331347 is a deficient number, since it is larger than the sum of its proper divisors (1).

232112003331347 is an equidigital number, since it uses as much as digits as its factorization.

232112003331347 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54432, while the sum is 35.

Adding to 232112003331347 its reverse (743133300211232), we get a palindrome (975245303542579).

The spelling of 232112003331347 in words is "two hundred thirty-two trillion, one hundred twelve billion, three million, three hundred thirty-one thousand, three hundred forty-seven".