Base | Representation |
---|---|
bin | 100001110001111011010… |
… | …111100011011111110101 |
3 | 22012220211000112120002111 |
4 | 201301323113203133311 |
5 | 301013112120041432 |
6 | 4534225304011021 |
7 | 326466161250223 |
oct | 41617327433765 |
9 | 8186730476074 |
10 | 2321352112117 |
11 | 815530827a35 |
12 | 315a88160a71 |
13 | 13ab96c2043c |
14 | 804d56c1b13 |
15 | 405b4e8d347 |
hex | 21c7b5e37f5 |
2321352112117 has 2 divisors, whose sum is σ = 2321352112118. Its totient is φ = 2321352112116.
The previous prime is 2321352112103. The next prime is 2321352112193. The reversal of 2321352112117 is 7112112531232.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2316831028996 + 4521083121 = 1522114^2 + 67239^2 .
It is a cyclic number.
It is not a de Polignac number, because 2321352112117 - 223 = 2321343723509 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2321352112817) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1160676056058 + 1160676056059.
It is an arithmetic number, because the mean of its divisors is an integer number (1160676056059).
Almost surely, 22321352112117 is an apocalyptic number.
It is an amenable number.
2321352112117 is a deficient number, since it is larger than the sum of its proper divisors (1).
2321352112117 is an equidigital number, since it uses as much as digits as its factorization.
2321352112117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5040, while the sum is 31.
Adding to 2321352112117 its reverse (7112112531232), we get a palindrome (9433464643349).
The spelling of 2321352112117 in words is "two trillion, three hundred twenty-one billion, three hundred fifty-two million, one hundred twelve thousand, one hundred seventeen".
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