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232141445153143 is a prime number
BaseRepresentation
bin110100110010000110100100…
…011000000100000101110111
31010102221111122110011221012021
4310302012210120010011313
5220411401134424400033
62141420150242134011
766616444263333631
oct6462064430040567
91112844573157167
10232141445153143
1167a706a7968269
1222052698351307
139c6bac9052186
1441479c4d95a51
151bc87e987ab2d
hexd321a4604177

232141445153143 has 2 divisors, whose sum is σ = 232141445153144. Its totient is φ = 232141445153142.

The previous prime is 232141445153099. The next prime is 232141445153153. The reversal of 232141445153143 is 341351544141232.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-232141445153143 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 232141445153143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (232141445153153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116070722576571 + 116070722576572.

It is an arithmetic number, because the mean of its divisors is an integer number (116070722576572).

Almost surely, 2232141445153143 is an apocalyptic number.

232141445153143 is a deficient number, since it is larger than the sum of its proper divisors (1).

232141445153143 is an equidigital number, since it uses as much as digits as its factorization.

232141445153143 is an evil number, because the sum of its binary digits is even.

The product of its digits is 691200, while the sum is 43.

Adding to 232141445153143 its reverse (341351544141232), we get a palindrome (573492989294375).

The spelling of 232141445153143 in words is "two hundred thirty-two trillion, one hundred forty-one billion, four hundred forty-five million, one hundred fifty-three thousand, one hundred forty-three".