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23220500335441 is a prime number
BaseRepresentation
bin1010100011110011100011…
…01011001000101101010001
310001012212011121000102001021
411101321301223020231101
511020421041041213231
6121215203421035441
74614424434141553
oct521716153105521
9101185147012037
1023220500335441
11744283909a3a2
1227303566b5b81
13cc58b737c3b6
145a3c41b5d4d3
152a404269c811
hex151e71ac8b51

23220500335441 has 2 divisors, whose sum is σ = 23220500335442. Its totient is φ = 23220500335440.

The previous prime is 23220500335433. The next prime is 23220500335511. The reversal of 23220500335441 is 14453300502232.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21046954588416 + 2173545747025 = 4587696^2 + 1474295^2 .

It is a cyclic number.

It is not a de Polignac number, because 23220500335441 - 23 = 23220500335433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 23220500335397 and 23220500335406.

It is not a weakly prime, because it can be changed into another prime (23220500335541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11610250167720 + 11610250167721.

It is an arithmetic number, because the mean of its divisors is an integer number (11610250167721).

Almost surely, 223220500335441 is an apocalyptic number.

It is an amenable number.

23220500335441 is a deficient number, since it is larger than the sum of its proper divisors (1).

23220500335441 is an equidigital number, since it uses as much as digits as its factorization.

23220500335441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 34.

Adding to 23220500335441 its reverse (14453300502232), we get a palindrome (37673800837673).

The spelling of 23220500335441 in words is "twenty-three trillion, two hundred twenty billion, five hundred million, three hundred thirty-five thousand, four hundred forty-one".