Base | Representation |
---|---|
bin | 1010100100001101010101… |
… | …01001110110010110101111 |
3 | 10001021011220012001020122201 |
4 | 11102012222221312112233 |
5 | 11021132412321420302 |
6 | 121225413050522331 |
7 | 4615424430435334 |
oct | 522065251662657 |
9 | 101234805036581 |
10 | 23234341201327 |
11 | 74486a0987833 |
12 | 2732b79a363a7 |
13 | cc6cb1a11979 |
14 | 5a479605098b |
15 | 2a45a2849c87 |
hex | 1521aaa765af |
23234341201327 has 2 divisors, whose sum is σ = 23234341201328. Its totient is φ = 23234341201326.
The previous prime is 23234341201301. The next prime is 23234341201361. The reversal of 23234341201327 is 72310214343232.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23234341201327 - 231 = 23232193717679 is a prime.
It is a super-2 number, since 2×232343412013272 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23234341202327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11617170600663 + 11617170600664.
It is an arithmetic number, because the mean of its divisors is an integer number (11617170600664).
Almost surely, 223234341201327 is an apocalyptic number.
23234341201327 is a deficient number, since it is larger than the sum of its proper divisors (1).
23234341201327 is an equidigital number, since it uses as much as digits as its factorization.
23234341201327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145152, while the sum is 37.
Adding to 23234341201327 its reverse (72310214343232), we get a palindrome (95544555544559).
The spelling of 23234341201327 in words is "twenty-three trillion, two hundred thirty-four billion, three hundred forty-one million, two hundred one thousand, three hundred twenty-seven".
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