Base | Representation |
---|---|
bin | 1101100001100011001… |
… | …0011100100100110101 |
3 | 211012201110102210012202 |
4 | 3120120302130210311 |
5 | 12301320043031123 |
6 | 254423140354245 |
7 | 22533463234631 |
oct | 3303062344465 |
9 | 735643383182 |
10 | 232344111413 |
11 | 8a59a214897 |
12 | 390436a5985 |
13 | 18baa23243b |
14 | b36199bdc1 |
15 | 609cc84a28 |
hex | 3618c9c935 |
232344111413 has 2 divisors, whose sum is σ = 232344111414. Its totient is φ = 232344111412.
The previous prime is 232344111397. The next prime is 232344111437. The reversal of 232344111413 is 314111443232.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 200634118084 + 31709993329 = 447922^2 + 178073^2 .
It is a cyclic number.
It is not a de Polignac number, because 232344111413 - 24 = 232344111397 is a prime.
It is a super-2 number, since 2×2323441114132 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (232344111463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116172055706 + 116172055707.
It is an arithmetic number, because the mean of its divisors is an integer number (116172055707).
Almost surely, 2232344111413 is an apocalyptic number.
It is an amenable number.
232344111413 is a deficient number, since it is larger than the sum of its proper divisors (1).
232344111413 is an equidigital number, since it uses as much as digits as its factorization.
232344111413 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6912, while the sum is 29.
Adding to 232344111413 its reverse (314111443232), we get a palindrome (546455554645).
The spelling of 232344111413 in words is "two hundred thirty-two billion, three hundred forty-four million, one hundred eleven thousand, four hundred thirteen".
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