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232411403131 is a prime number
BaseRepresentation
bin1101100001110011001…
…1001001001101111011
3211012220011001120002121
43120130303021031323
512301434304400011
6254433542542111
722535241221455
oct3303463111573
9735804046077
10232411403131
118a6241a6086
1239062137937
1318bbb16331b
14b36a8b72d5
1560a3b27e71
hex361ccc937b

232411403131 has 2 divisors, whose sum is σ = 232411403132. Its totient is φ = 232411403130.

The previous prime is 232411403083. The next prime is 232411403141. The reversal of 232411403131 is 131304114232.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 232411403131 - 223 = 232403014523 is a prime.

It is a super-2 number, since 2×2324114031312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 232411403096 and 232411403105.

It is not a weakly prime, because it can be changed into another prime (232411403141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116205701565 + 116205701566.

It is an arithmetic number, because the mean of its divisors is an integer number (116205701566).

Almost surely, 2232411403131 is an apocalyptic number.

232411403131 is a deficient number, since it is larger than the sum of its proper divisors (1).

232411403131 is an equidigital number, since it uses as much as digits as its factorization.

232411403131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 232411403131 its reverse (131304114232), we get a palindrome (363715517363).

The spelling of 232411403131 in words is "two hundred thirty-two billion, four hundred eleven million, four hundred three thousand, one hundred thirty-one".