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232431133021781 is a prime number
BaseRepresentation
bin110100110110010100010111…
…000111100101011001010101
31010110222012101022000102002012
4310312110113013211121111
5220431122430023144111
62142201215522354005
766646411103520341
oct6466242707453125
91113865338012065
10232431133021781
116807254313a651
122209a8641bb905
139c90214608ab5
144157a26724621
151bd1101a7348b
hexd365171e5655

232431133021781 has 2 divisors, whose sum is σ = 232431133021782. Its totient is φ = 232431133021780.

The previous prime is 232431133021753. The next prime is 232431133021807. The reversal of 232431133021781 is 187120331134232.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 214633956452881 + 17797176568900 = 14650391^2 + 4218670^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-232431133021781 is a prime.

It is a super-2 number, since 2×2324311330217812 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (232431133021981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116215566510890 + 116215566510891.

It is an arithmetic number, because the mean of its divisors is an integer number (116215566510891).

Almost surely, 2232431133021781 is an apocalyptic number.

It is an amenable number.

232431133021781 is a deficient number, since it is larger than the sum of its proper divisors (1).

232431133021781 is an equidigital number, since it uses as much as digits as its factorization.

232431133021781 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 145152, while the sum is 41.

The spelling of 232431133021781 in words is "two hundred thirty-two trillion, four hundred thirty-one billion, one hundred thirty-three million, twenty-one thousand, seven hundred eighty-one".