Base | Representation |
---|---|
bin | 10101101001011010… |
… | …100101001010011001 |
3 | 2012222212120200020121 |
4 | 111221122211022121 |
5 | 340100303141441 |
6 | 14402230553241 |
7 | 1451664512626 |
oct | 255132451231 |
9 | 65885520217 |
10 | 23243412121 |
11 | 9948333606 |
12 | 4608208821 |
13 | 22656360c7 |
14 | 11a6d7134d |
15 | 910891dd1 |
hex | 5696a5299 |
23243412121 has 2 divisors, whose sum is σ = 23243412122. Its totient is φ = 23243412120.
The previous prime is 23243412109. The next prime is 23243412149. The reversal of 23243412121 is 12121434232.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13733261721 + 9510150400 = 117189^2 + 97520^2 .
It is a cyclic number.
It is not a de Polignac number, because 23243412121 - 217 = 23243281049 is a prime.
It is not a weakly prime, because it can be changed into another prime (23243412161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11621706060 + 11621706061.
It is an arithmetic number, because the mean of its divisors is an integer number (11621706061).
Almost surely, 223243412121 is an apocalyptic number.
It is an amenable number.
23243412121 is a deficient number, since it is larger than the sum of its proper divisors (1).
23243412121 is an equidigital number, since it uses as much as digits as its factorization.
23243412121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2304, while the sum is 25.
Adding to 23243412121 its reverse (12121434232), we get a palindrome (35364846353).
The spelling of 23243412121 in words is "twenty-three billion, two hundred forty-three million, four hundred twelve thousand, one hundred twenty-one".
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