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23253440437 is a prime number
BaseRepresentation
bin10101101010000000…
…110101011110110101
32020000120110011111201
4111222000311132311
5340110340043222
614403225532501
71452145660663
oct255200653665
966016404451
1023253440437
119952a62a77
12460b644131
132267737816
1411a8421c33
159116c3427
hex56a0357b5

23253440437 has 2 divisors, whose sum is σ = 23253440438. Its totient is φ = 23253440436.

The previous prime is 23253440347. The next prime is 23253440447. The reversal of 23253440437 is 73404435232.

Together with previous prime (23253440347) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18689897521 + 4563542916 = 136711^2 + 67554^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23253440437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 23253440396 and 23253440405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23253440447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11626720218 + 11626720219.

It is an arithmetic number, because the mean of its divisors is an integer number (11626720219).

Almost surely, 223253440437 is an apocalyptic number.

It is an amenable number.

23253440437 is a deficient number, since it is larger than the sum of its proper divisors (1).

23253440437 is an equidigital number, since it uses as much as digits as its factorization.

23253440437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 241920, while the sum is 37.

Adding to 23253440437 its reverse (73404435232), we get a palindrome (96657875669).

The spelling of 23253440437 in words is "twenty-three billion, two hundred fifty-three million, four hundred forty thousand, four hundred thirty-seven".