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23261556440149 is a prime number
BaseRepresentation
bin1010100101000000000001…
…10011101111110001010101
310001100210010212022121211221
411102200000303233301111
511022104131422041044
6121250113403530341
74620410024235046
oct522400063576125
9101323125277757
1023261556440149
117459197201545
1227382b42299b1
13cc972b183a91
145a5c186c08cd
152a5146c49484
hex152800cefc55

23261556440149 has 2 divisors, whose sum is σ = 23261556440150. Its totient is φ = 23261556440148.

The previous prime is 23261556440117. The next prime is 23261556440153. The reversal of 23261556440149 is 94104465516232.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21820044043249 + 1441512396900 = 4671193^2 + 1200630^2 .

It is a cyclic number.

It is not a de Polignac number, because 23261556440149 - 25 = 23261556440117 is a prime.

It is a super-2 number, since 2×232615564401492 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23261556440096 and 23261556440105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23261556440179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11630778220074 + 11630778220075.

It is an arithmetic number, because the mean of its divisors is an integer number (11630778220075).

Almost surely, 223261556440149 is an apocalyptic number.

It is an amenable number.

23261556440149 is a deficient number, since it is larger than the sum of its proper divisors (1).

23261556440149 is an equidigital number, since it uses as much as digits as its factorization.

23261556440149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6220800, while the sum is 52.

The spelling of 23261556440149 in words is "twenty-three trillion, two hundred sixty-one billion, five hundred fifty-six million, four hundred forty thousand, one hundred forty-nine".